For all your questions, big or small, IDNLearn.com has the answers you need. Join our community to access reliable and comprehensive responses to your questions from experienced professionals.
Sagot :
Answer:
212 gm of CH2Cl2 are formed
Explanation:
4.6 CONCEPT ASSESSMENT Suppose that each of these reactions has a 90% yield. CH4(g) + Cl2(g) - CH2Cl(g) + HCl(g) CH3Cl(g) + Cl2(g) - CH2Cl20) + HCl(g) Starting with 50.0 g CH4 in the first reaction and an excess of Cl2(g), the number of grams of CH2Cl2 formed in the second reaction is (a) 50.0 X 0.81 x (85/16) (c) 50.0 X 0.90 X 0.90 (b) 50.0 X 0.90 (d) 50.0 X 0.90 X 0.90 < (16/50.5)(70.9/85)H
1st, rewrite the equations so you can see the problem easier
reaction (1) CH4 +Cl2--------->CH3CL + HCl
reaction (2) CH3Cl + Cl2------> CH2Cl2 + HCl
the product ib reaction (1) is CH3Cl and is formed with a 90% yield.
90% of the reactant methane iis converted to methyk chloride.
methane (CH4) has a molar mass of 12 + 4X1 =16
you start with 50.0 gm of CH4,
SO
50.0/16 =3.125 moles of CH4
90% of this become methyl choride...CH3Cl
SO
0.90 X 3.125 = 2.8 moles of CH3Cl are formed
NOTE 90% HAS ONLY 2 SIGNIFICANT FIGURES SO YOU ARE LIMITED TO 2 SIGNIFICANT FIGURES IN YOUR CALCULATION!
in reaction(2) 1 mole of methyl chloride becomes methyl dichloromethane yi
with again a 90% yield
0.90 X 2.8 = 2.5 moles of CH2Cl2 are formed
so
2.5 moles of CH2Cl2 are formed.
CH2Cl2 has a molar mass of 12 + 2X1 + 2X35.5 =
12 + 2 + 71 =85
1 mole weighs 85 gm
2.5 moles weigh 2.5 X 85 = 212 gm
X
We appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. IDNLearn.com has the solutions to your questions. Thanks for stopping by, and see you next time for more reliable information.
