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can anyone help please im havinga prblem in this thank u

Can Anyone Help Please Im Havinga Prblem In This Thank U class=

Sagot :

Genmadidn

Yeah Bro ! I'm here ,

.Given that ;-

slope ( m) = 3/2

y-intercept (c) = -3

Now ,

we know the equation of straight line in slope intercept form;

I.e

y = mx+c

Just substitute m and c 's value , we get

y= (3/2)x +( -3)

or,. y = 3x/2 - 3

[tex]y = \frac{3x}{2} - 3 \\ y = \frac{3x - 6}{2} \\ 2y = 3x - 6 \\ 3x - 2y = 6\\ [/tex]

,

Hence 3x-2y = .6

3x-2y-6 =0 is the required equation.

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