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Simplify
7^8x 7^3x 7^4
———————-
7^9x 7^5

Sagot :

Devishri1977idn

Answer:

7

Step-by-step explanation:

[tex]a^{m}*a^{n}=a^{m+n}\\\\\\\dfrac{a^{m}}{a^{n}}=a^{m-n}\\\\\\\dfrac{7^{8}*7^{3}*7^{4}}{7^{9}*7^{5}}=\dfrac{7^{8+3+4}}{7^{9+5}}\\\\=\dfrac{7^{15}}{7^{14}}\\\\\\=7^{15-14}=7^{1}\\\\= 7[/tex]

Aysha20164idn

Answer:

7^1

Step-by-step explanation:

since all the bases are same, we're going to use the law (a^m × a^n = a^m+n)

8+3+4= 15, hence, it's 7^15

we'll apply the same law for the denominator, 9+5= 14, so we'll get 7^15 ÷ 7^14

next we're gonna use the law (a^m ÷ a^n = a^m-n where m>n)

15-14 = 1

so our final answer is 7^1

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