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Third-degree, with zeros of -3,-2, and 1, and passes through the point (3,9)

Sagot :

Three zeroes of a third-degree polynomial are given, with the graph passing through the point (3,6). To find the equation of this, first, let us set up how a 3rd-degree polynomial factored out should look like:  

y =  a(x+b)(x+c)(x+d).

Since the zeroes of the function are -3, -2, 1, the equation will look like y = a(x+3)(x+2)(x-1). To solve for a, plug-in x = 3 and y = 6 from the point (3,6). After replacing the variable a in the equation with the answer, you will have the solution for the problem.

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