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how do I solve 4(x+3)=-6(4y-2)

Sagot :

Answer:

x=-6y

Step-by-step explanation:

Divide both sides by 4:

[tex]\frac{4\left(x+3\right)}{4}=\frac{-6\left(4y-2\right)}{4}[/tex]

Simplify to give:

x+3 = -3(2y-1)

Subtract 3 from both sides:

x+3-3 = -3(2y-1)-3

Simplify to give your answer:

x=-6y

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