Schelsie53idn
Answered

Explore a vast range of topics and get informed answers at IDNLearn.com. Join our Q&A platform to access reliable and detailed answers from experts in various fields.

Please help me with thissss

Please Help Me With Thissss class=

Sagot :

Answer:

see explanation

Step-by-step explanation:

Using the rule of radicals

[tex]\sqrt{a}[/tex] × [tex]\sqrt{b}[/tex] ⇔ [tex]\sqrt{ab}[/tex]

(a)

[tex]\sqrt{3}[/tex] × [tex]\sqrt{6}[/tex]

= [tex]\sqrt{3(6)}[/tex]

= [tex]\sqrt{18}[/tex]

= [tex]\sqrt{9(2)}[/tex]

= [tex]\sqrt{9}[/tex] × [tex]\sqrt{2}[/tex]

= 3[tex]\sqrt{2}[/tex]

(b)

[tex]\sqrt{8}[/tex] × [tex]\sqrt{18}[/tex]

= [tex]\sqrt{8(18)}[/tex]

= [tex]\sqrt{144}[/tex]

= 12

HayabusaBrainlyidn

>> Answer

_________

  • Number (A.)

[tex] \sqrt{3} \times \sqrt{6} = ...[/tex]

[tex] = \sqrt{3 \times 6} [/tex]

[tex] = \sqrt{18} [/tex]

[tex] = \sqrt{9} \sqrt{2} [/tex]

[tex] = \bold{3 \sqrt{2}} [/tex]

.

  • Number (B.)

[tex] \sqrt{8} \times \sqrt{18} = ...[/tex]

[tex] = \sqrt{8 \times 18} [/tex]

[tex] = \sqrt{144} = \bold{12}[/tex]

Thank you for being part of this discussion. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Find the answers you need at IDNLearn.com. Thanks for stopping by, and come back soon for more valuable insights.