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PLEASE HELP DUE SOON PLEASE !!

PLEASE HELP DUE SOON PLEASE class=

Sagot :

Answer:

(1 + \sqrt{3} ) : 3

Step-by-step explanation:

AB = x[tex]\sqrt{3} cm[/tex]

BC = x cm

Area = l * b = x[tex]\sqrt{3}[/tex] * x

= x^2 [tex]\sqrt{3}[/tex]

EFG is equilateral triangle

EF = y cm

Area of triangle = [tex](\sqrt{3} / 4) * a^{2}[/tex]

A = (\sqrt{3} / 4) * y^{2}

As both areas are equal

[tex]\sqrt{3} x^{2} = \sqrt{3} /4 * y^{2}[/tex]

[tex]4x^{2} = y^{2}[/tex]

2x = y

perimeter of ABCD = 2 (l + b)

[tex]2 (x\sqrt{3} + x)\\= 2x(\sqrt{3} + 1)[/tex]

perimeter of EFG = 3y

so ratio is [tex]2x(\sqrt{3} + 1) : 3y[/tex]

substitute y = 2x

[tex]2x(\sqrt{3} + 1) : 3*2x\\(\sqrt{3} + 1) : 3[/tex]

[tex](1 + \sqrt{3} ) : 3[/tex]

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