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Sagot :
First, solve for y.
1/3x - 1/6y = 0
-1/3x -1/3x
-1/6y = -1/3x (divide by -1/6, you basicallt multiply by -6)
y = 2x
1/3x - 1/6y = 0
-1/3x -1/3x
-1/6y = -1/3x (divide by -1/6, you basicallt multiply by -6)
y = 2x
[tex]\frac{1}{3}x- \frac{1}{6}y=0 \\ \\\frac{1}{6}y = \frac{1}{3}x \ \ /*6 \\ \\y=\frac{1}{\not3^1}x*\not6^2 \\ \\y=2x[/tex]
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