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What is the square root of x^6 over y^4

Sagot :

The answer is the square root of 6*X over 2
[tex]\sqrt\frac{x^6}{y^4}=\frac{\sqrt{x^6}}{\sqrt{y^4}}=\frac{\sqrt{x^{3\cdot2}}}{\sqrt{y^{2\cdot2}}}=\frac{\left(\sqrt{x^2}\right)^3}{\left(\sqrt{y^2}\right)^2}=\frac{|x|^3}{|y|^2}=\frac{|x|^3}{y^2}\\\\\\\\y\neq0[/tex]