[tex]y-y_1=m(x-x_1) \\ \\
m=-\frac{5}{8} \\
(-10,-6) \\
x_1=-10 \\
y_1=-6 \\
\Downarrow \\
y-(-6)=-\frac{5}{8}(x-(-10)) \\
\boxed{y+6=-\frac{5}{8}(x+10)} \ - \ \hbox{the point-slope form} \\ \\
y+6=-\frac{5}{8}(x+10) \\
y+6=-\frac{5}{8}x-\frac{50}{8} \\
y=-\frac{5}{8}x-\frac{50}{8}-6 \\
y=-\frac{5}{8}x-\frac{25}{4}-\frac{24}{4} \\
y=-\frac{5}{8}x-\frac{49}{4} \\
\boxed{y=-\frac{5}{8}x-12 \frac{1}{4}} \ - \ \hbox{the slope-intercept form}[/tex]
