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solve for x 27^(2x+4)=1/9^(x-46)

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[tex]27^{2x+4}=(\frac{1}{9})^{x-46} \\ (3^3)^{2x+4}=(3^{-2})^{x-46} \\ 3^{3(2x+4)}=3^{-2(x-46)} \\ 3^{6x+12}=3^{-2x+92} \\ 6x+12=-2x+92 \\ 6x+2x=92-12 \\ 8x=80 \\ x=10[/tex]
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