Answered

Expand your horizons with the diverse and informative answers found on IDNLearn.com. Join our Q&A platform to get accurate and thorough answers to all your pressing questions.

A 5.77 kg object is tied to the end of a cord and whirled in a horizontal circle of radius 355 cm. The object completes 4.4 revolutions every 6.94E-3 hours. What is the centripetal force exerted on the object?

Sagot :

Onyebuchinnajiidn

The centripetal force exerted on the object is 25.24 N.

The given parameters:

  • mass of the object, m = 5.77 kg
  • radius of the circle, r = 355 cm = 3.55 m
  • number of revolutions, N = 4.4 rev for 6.9 x 10⁻³ hours

The angular speed of the object is calculated as follows;

[tex]\omega = \frac{4.4 \ rev}{6.9 \times 10^{-3} \ h} \times \frac{1 \ h}{3600 \ s} \times \frac{2 \ \pi \ rad}{1 \ rev} = 1.11 \ rad/s[/tex]

The centripetal force exerted on the object is calculated as follows;

[tex]F =m \omega ^2 r\\\\F = 5.77 \times (1.11)^2 \times 3.55\\\\F = 25.24 \ N[/tex]

Thus, the centripetal force exerted on the object is 25.24 N.

Learn more about centripetal force here: https://brainly.com/question/20905151

Your participation means a lot to us. Keep sharing information and solutions. This community grows thanks to the amazing contributions from members like you. Your questions deserve accurate answers. Thank you for visiting IDNLearn.com, and see you again for more solutions.