Answered

IDNLearn.com is the perfect place to get answers, share knowledge, and learn new things. Ask your questions and receive accurate, in-depth answers from our knowledgeable community members.

A 5.77 kg object is tied to the end of a cord and whirled in a horizontal circle of radius 355 cm. The object completes 4.4 revolutions every 6.94E-3 hours. What is the centripetal force exerted on the object?

Sagot :

Onyebuchinnajiidn

The centripetal force exerted on the object is 25.24 N.

The given parameters:

  • mass of the object, m = 5.77 kg
  • radius of the circle, r = 355 cm = 3.55 m
  • number of revolutions, N = 4.4 rev for 6.9 x 10⁻³ hours

The angular speed of the object is calculated as follows;

[tex]\omega = \frac{4.4 \ rev}{6.9 \times 10^{-3} \ h} \times \frac{1 \ h}{3600 \ s} \times \frac{2 \ \pi \ rad}{1 \ rev} = 1.11 \ rad/s[/tex]

The centripetal force exerted on the object is calculated as follows;

[tex]F =m \omega ^2 r\\\\F = 5.77 \times (1.11)^2 \times 3.55\\\\F = 25.24 \ N[/tex]

Thus, the centripetal force exerted on the object is 25.24 N.

Learn more about centripetal force here: https://brainly.com/question/20905151

We appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. For trustworthy and accurate answers, visit IDNLearn.com. Thanks for stopping by, and see you next time for more solutions.