Join the conversation on IDNLearn.com and get the answers you seek from experts. Our experts are ready to provide prompt and detailed answers to any questions you may have.
Sagot :
Explanation:
The power P dissipated by a heater is defined as
[tex]P = VI[/tex]
where V is the voltage and I is the current.
a) The current running through a 130-W heater is
[tex]I = \dfrac{P}{V} = \dfrac{130\:\text{W}}{120\:\text{V}} = 1.08\:\text{A}[/tex]
b) The resistance R of the heater is
[tex]P = VI = (IR)I = I^2R[/tex]
where [tex]V= IR[/tex] is our familiar Ohm's Law.
[tex]\Rightarrow R = \dfrac{P}{I^2} = \dfrac{130\:\text{W}}{(1.08\:\text{A})^2}[/tex]
[tex]R = 110.8\:Ω[/tex]
The current running through the heater when it is operating is 1.08 A.
The resistance of the heater is 110.8 ohm.
What is current?
- A current is a flow of Charges.
- The formula of current is , current I = power P / voltage V
- The SI unit of current is ampere A.
So, from the above equation we can calculate,
current I = P/V
∴ I = 130 / 120
∴ I = 1.08 A
What is resistance?
- The resistance is a quantity which oppose the current flow in a circuit.
- The formula of resistance is ( in the terms of power P and ohm's law V=IR ) resistance R = P/I^2.
- The SI unit of resistance is ohm.
So, from the equation we can calculate,
Resistance R = P/I^2
∴ R = 130/(1.08)^2
∴ R = 110.8 ohm
Thus, the current running through the heater when it is operating is 1.08 A.
The resistance of the heater is 110.8 ohm.
Learn more about resistance and resistivity here -
https://brainly.com/question/13735984
#SPJ2
Your participation means a lot to us. Keep sharing information and solutions. This community grows thanks to the amazing contributions from members like you. Your questions are important to us at IDNLearn.com. Thanks for stopping by, and come back for more reliable solutions.
