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ROUND FINAL ANSWER TO 2 DECIMAL PLACES AND DO NOT INCLUDE A UNIT 675 mL of a gas at a pressure of 1.5atm is compressed to 345 mL. What is the new pressure of the gas?​

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This problem is providing the initial volume and pressure of a gas as 675 mL and 1.5 atm and then mentions the final volume as 345 mL and asks for the new pressure of the gas.

Thus, we start off this problem by recalling the concept of Boyle's law as an inversely proportional relationship between pressure and volume:

[tex]P_1V_1=P_2V_2[/tex]

In which we solve for the final pressure, [tex]P_2[/tex] as shown below:

[tex]P_2=\frac{P_1V_1}{V_2} \\\\\\P_2=\frac{675mL*1.5atm}{345mL} \\\\\\P_2=2.93atm[/tex]

Considering we had to cancel out the milliliters to obtain atm as units of pressure.

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