Join IDNLearn.com to access a wealth of knowledge and get your questions answered by experts. Find reliable solutions to your questions quickly and accurately with help from our dedicated community of experts.

Suppose y varies jointly as x and z. What is y when x = 2 and z = 3, if y = 20 when x = 4 and z = 3?

Sagot :

Answer:

y = 10

Step-by-step explanation:

Given y varies jointly as x and z then the equation relating them is

y = kxz ← k is the constant of variation

To find k use the condition y = 20 when x = 4 and z = 3 , then

20 = k × 4 × 3 = 12k ( divide both sides by 12 )

[tex]\frac{20}{12}[/tex] = k , that is

k = [tex]\frac{5}{3}[/tex]

y = [tex]\frac{5}{3}[/tex] xz ← equation of variation

When x = 2 and z = 3 , then

y = [tex]\frac{5}{3}[/tex] × 2 × 3 = 5 ×  2 = 10