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QUESTION 2

What is the pressure in atm of 0.742 mole of gas at 10.91 L and 291 K?

I

Sagot :

Lanuelidn

The pressure of this gas in atm is equal to 1.63 atm.

Given the following data:

  • Number of moles = 0.742 mole
  • Volume = 10.91 Liters
  • Temperature = 291 K
  • Ideal gas constant, R = 0.0821 Latm/molK

To calculate the pressure of this gas, we would use the ideal gas law equation;

[tex]P=\frac{nRT}{V}[/tex]

Where;

  • P is the pressure.
  • V is the volume.
  • n is the number of moles of a gas.
  • R is the ideal gas constant.
  • T is the temperature.

Substituting the given parameters into the formula, we have;

[tex]P=\frac{0.742 \times 0.0821 \times 291}{10.91} \\\\P = \frac{17.73}{10.91}[/tex]

Pressure, P = 1.63 atm.

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