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What is an equation of the line that passes through the points (6,-3) and (-6,-5)

Sagot :

Kocatboiidn

Answer:

y = 6x - 4

Step-by-step explanation:

I drew a graph slope formula is (y2 - y1)/(x2 - x1) and if the line passes through a point that is not zero (in this case it does) we add or subtract that as the y-intercept. we recently passed this so I know it.

Slope-intercept form: (y = mx + b) y = 6x - 4

Standard form: (Ax + By = C) -6x + y = -4

Point-slope form: (y - y1 = m (x - x1)) (let's use the point (6, -3)) y + 3 = 6 (x - 6)

Tell me if I'm wrong :)

Ma5007482idn

Answer:

Step-by-step explanation:

Bu using the formula of Two-Points form:

[tex]\frac{y-y_{1} }{y_{2}-y_{1} } =\frac{x-x_{1} }{x_{2}-x_{1} }[/tex]

Substitute the points in the above equation:

y+3/-5+3=x-6/-6-6

y+3/-2=x-6/-12

-12(y+3)=-2(x-6)

-12y-24=-2x+6

2x-12y-24-6=0

2x-12y-30=0

Or

x-6y-15=0

If you need to ask any question,let me know.

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