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A double-pane glass window is 60.0 cm x 90.0 cm and has 3.00-mm window panes. If the temperature difference between inside and outside is 24.0 K, how far apart should the panes be to have a heat loss of 4.09 W? Assume there is air in the gap.

A Doublepane Glass Window Is 600 Cm X 900 Cm And Has 300mm Window Panes If The Temperature Difference Between Inside And Outside Is 240 K How Far Apart Should T class=

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The distance between the glass to have the given heat loss is 2.54 m.

The given parameters:

  • dimension of the window, = 60 cm by 90 cm
  • temperature, T = 24 K
  • heat lost, Q = 4.09 W
  • thermal conductivity of glass, k = 0.8 W/mK

The area of the glass window is calculated as follows;

[tex]A = 0.6 \times 0.9\\\\A = 0.54 \ m^2[/tex]

The distance between the glass is calculated as follows;

[tex]Q = \frac{KA \Delta T}{\Delta x} \\\\\Delta x = \frac{kA \Delta T}{Q} \\\\\Delta x = \frac{0.8 \times 0.54 \times 24 }{4.09} \\\\\Delta x = 2.54 \ m[/tex]

Thus, the distance between the glass to have the given heat loss is 2.54 m.

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