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Sagot :
Answer:
Copies cost for the first case = $ 12
Copies cost for the second case =$16
Number of Copies = 4
Step-by-step explanation:
Let the number of copies = N
. for the first case: total cost (T1) = 38 + 3N
. for the second case: total cost (T2) = 34 + 4N
Determine the ‘N’ when the cost is equivalent
So, 38 + 3N = 34 + 4N
38 – 34 = 4N – 3N
N = 4
Therefore, number of copies = 4
Copies cost for the first case = 3 × 4 = $12
Copies cost for the second case = 4 × 4 = $16
#1.
- Set up fee=$38
- Cost per copy=$3
Expression
[tex]\sf\longmapsto 38+3x[/tex]
#2
- Set up fee=$34
- Cost per copy=$4
Expression
[tex]\sf\longmapsto 34+4x[/tex]
Now
[tex]\sf\longmapsto 4x+34=3x+38[/tex]
[tex]\sf\longmapsto x=4[/tex]
There were 4copies
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