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Sagot :
The work done onto the car is 506,250 J
The work done on a system implies an increase in the internal energy of the system as a result of some forces acting on the system from the outside.
From the parameters given:
- The mass of the car = 1500 kg
- The initial speed = 30 m/s
- The final speed = 15 m/s
The work done onto the car refers to the change in the kinetic energy (i.e. ΔK.E)
[tex]\mathbf{=\dfrac{1}{2} mv_1^2 -\dfrac{1}{2} mv_2^2}[/tex]
[tex]\mathbf{=\dfrac{1}{2} m(v_1^2 - v_2^2)}[/tex]
[tex]\mathbf{=\dfrac{1}{2} \times 1500 \times (30^2 - 15^2)}[/tex]
= 506,250 J
Therefore, we can conclude that the work done on the car is 506,250 J
Learn more about work done here:
https://brainly.com/question/18762601
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