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A 98% confidence interval is found to be (32,46). What is the margin of error ?

Sagot :

Using confidence interval concepts, it is found that the margin of error is of 7.

  • A confidence interval has the format (a,b).
  • The margin of error is half the difference between the two bounds, that is:

[tex]M = \frac{b - a}{2}[/tex]

In this problem, the interval is (32, 46), hence [tex]b = 46, a = 32[/tex], and the margin of error is:

[tex]M = \frac{46 - 32}{2} = 7[/tex]

The margin of error is of 7.

A similar problem is given at https://brainly.com/question/25704940

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