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Sagot :
Using the probability table, it is found that:
a) There is a 0.25 = 25% probability that this couple spends 45 dollars or more.
b) The expected amount the couple actually has to pay is $36.85.
From the table, the probabilities of each total cost are:
[tex]P(X = 30) = P(X = 15|Y = 15) = 0.2[/tex]
[tex]P(X = 35) = P(X = 15|Y = 20) + P(X = 20|Y = 15) = 0.15 + 0.15 = 0.3[/tex]
[tex]P(X = 40) = P(X = 15|Y = 25) + P(X = 20|Y = 20) + P(X = 25|Y = 15) = 0.05 + 0.15 + 0.05 = 0.25[/tex]
[tex]P(X = 45) = P(X = 20|Y = 25) + P(X = 25|Y = 20) = 0.1 + 0.1 = 0.2[/tex]
[tex]P(X = 50) = P(X = 25|Y = 25) = 0.05[/tex]
Item a:
This probability is:
[tex]P(X \geq 45) = P(X = 45) + P(X = 50) = 0.2 + 0.05 = 0.25[/tex]
There is a 0.25 = 25% probability that this couple spends 45 dollars or more.
Item b:
The expected value is the sum of each outcome multiplied by it's respective probability.
- For X = 45 and X = 50, the value is multiplied by 0.9, due to the discount.
Hence:
[tex]E(X) = 0.2(30) + 0.3(35) + 0.25(40) + 0.9[0.2(45) + 0.05(50)] = 36.85[/tex]
The expected amount the couple actually has to pay is $36.85.
A similar problem is given at https://brainly.com/question/24855677
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