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If f(x)=3^x, then f(-2)= ?
A.1/9
B.9
C.-6
D.-9


Sagot :

You start by plugging in x=-2 into f(x)
f(-2) = 3^-2
Which gives you
f(-2) = 1/3^2 since negative exponents change the number to a dividend.
Then you square the 3
f(-2) = 1/9 or .111 repeating
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