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A compound microscope is an instrument which consists of two lenses L1 and L2. The lens L1 called objective forms a real inverted and magnified image of the given object. This serves as the object for the second lens L2 the eye piece. The eye piece functions like a simple microscope or magnifier. It produces the final image which is inverted with respect to the original object, enlarged and virtual

What is the value and sign of {according to the new cartesian sign convention} magnification of the image formed by L2?

Sagot :

The characteristics of the magnification allow you to find what the total magnification of a microscope is:

  • The image formed by the microscope is inverted with respect to the initial object.
  • The magnification depends on the distance between the two lenses and its focal length.

A microscope is an instrument used to magnify the size of nearby objects. Its principle of operation, the two lenses L₁ and L₂ are widely separated, which is why they work as independent lenses, consequently the magnification of the microscope is the product of the magnification of each element.

         M = m₁ m₂  

         [tex]M = - \frac{L}{f_{objetive}} \ \frac{25 \ cm }{f_{oclar}}[/tex]  

where M is the total magnification, m₁ and m₂ the magnification of each element, L the distance between the lenses, ”25 cm” the focal length for near vision and f the focal length

The image formed by the microscope is inverted with respect to the objet, see  attached.

The magnification depends on the distance between the two lenses and its focal length.

In conclusion using the characteristics of the magnification we can find what the total magnification of a microscope is:

  • The image formed by the microscope is inverted with respect to the initial object.

  • The magnification depends on the distance between the two lenses and its focal length.

Learn more about compound microscopes here: brainly.com/question/10336291

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