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Your parents put in fencing around the walkway for safety. If 110 feet of fencing is used, what are the dimensions of the pool?

Sagot :

The dimension of the pool has a length of 27.5 feet and width of 27.5 feet.

Let x represent the length of the pool and y represent the width of the pool

Perimeter = 2(length + width)

110 = 2(x + y)

x + y = 55

y = 55 - x

Area (A) = length * width

A = x * y

A = x(55 - x)

A = 55x - x²

The maximum area is at dA/dx = 0, hence:

dA/dx = 55 - 2x

0 = 55 - 2x

2x = 55

x = 27.5 feet

y = 55 - x = 55 - 27.5

y = 27.5 feet

The dimension of the pool has a length of 27.5 feet and width of 27.5 feet.

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