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secret_num = 10 temp = secret_num + 8 #evaluate secret + 8, and put the result #in temp temp = temp * 2 #evaluate temp * 2, and put the results #in temp temp = temp / 4 answer = temp - secret_num / 2 print(answer)
why is the result always 4 ?why doesn't it change?​

Sagot :

Batolisisidn

The result will always be 4 because the first four lines of code gets a number [tex]k+4[/tex], where [tex]k=\frac{\text{secret num}}{2}[/tex], and the last line subtracts [tex]4[/tex] from [tex]k+4[/tex].. therefore leaving us with the value [tex]4[/tex].

The effect of each line is explained below:

secret_num = 10

Assigns the value 10 to secret_num

temp = secret_num + 8

Stores the value 18 in temp

temp = temp * 2

Stores the value 36 in temp

temp = temp / 4

Stores the value 9 in temp

answer = temp - secret_num / 2

Stores the value 4 in answer

If the reasoning were done algebraically, we would have

[tex](((\text{secret num} + 8)\times 2)/4)-\text{secret num}/2\\[/tex]

Where the bracket nesting reflects the sequence of operations that led to the final answer in the code

Writing it mathematically, and simplifying

[tex]\frac{2(\text{secret num} + 8)}{4}-\frac{\text{secret num}}{2}\\\\=\frac{2\times\text{secret num} + 16}{4}-\frac{\text{secret num}}{2}\\\\=\frac{\text{secret num}}{2}+4-\frac{\text{secret num}}{2}\\\\=\frac{\text{secret num}}{2}-\frac{\text{secret num}}{2}+4\\\\=4[/tex]

We see that at the end, no matter what the value of secret_num was, the secret_num term still cancels out, leaving us with 4.

Learn more about Arithmetic operations here: https://brainly.com/question/5973382

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