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What is an equation of the axis of symmetry for the parabola whose equation is y=2x^2 + 8x-1

Sagot :

Answer:

x = - 2

Step-by-step explanation:

The equation of the axis of symmetry is a vertical line with equation

x = c

where c is the value of the x- coordinate of the vertex

The x- coordinate of the vertex is

x = - [tex]\frac{b}{2a}[/tex]

Given

y = 2x² + 8x - 1

with a = 2 and b = 8 , then

x = - [tex]\frac{8}{4}[/tex] = - 2

x = - 2 is the equation of the axis of symmetry

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