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Sagot :
[tex](2n+2)(2n-2)\\\\=(2n)^2 -2^2 ~~~~~~;[a^2 -b^2 =(a-b)(a+b)]\\\\=4n^2 -4[/tex]
Answer:
A) 4n²- 4
Step-by-step explanation:
use the FOIL method:
F = first, meaning multiply the 1st terms in each factor
O = outer, meaning multiply the 1st term in first factor and last term in second
I = inner, meaning multiply the 2nd term in first factor and 1st term in second
L = last, meaning multiply the last terms in each factor
F = 2n · 2n = 4n²
O = 2n(-2) = -4n
I = 2(2n) = 4n
L = 2(-2) = -4
you have 4n² - 4n + 4n - 4
this can be simplified by adding the two middle terms (which will zero out):
4n²- 4
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