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A 1050 W carbon-dioxide laser emits light with a wavelength of 10μm into a 3.0-mm-diameter laser beam. What force does the laser beam exert on a completely absorbing target?

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The force exerted by the laser beam on a completely absorbing target is [tex]3.5 \times 10^{-6} \ N[/tex].

The given parameters;

  • power of the laser light, P = 1050 W
  • wavelength of the emitted light, λ = 10 μm

The speed of the emitted laser light is given as;

v = 3 x 10⁸ m/s

The force exerted by the laser beam on a completely absorbing target is calculated as follows;

P = Fv

[tex]F = \frac{P}{v} \\\\F = \frac{1050}{3\times 10^8} \\\\F = 3.5 \times 10^{-6} \ N[/tex]

Thus, the force exerted by the laser beam on a completely absorbing target is [tex]3.5 \times 10^{-6} \ N[/tex].

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