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Suppose a normal distribution has a mean of 62 and a standard deviation of
4. What is the probability that a data value is between 59 and 67? Round your
answer to the nearest tenth of a percent.

Suppose A Normal Distribution Has A Mean Of 62 And A Standard Deviation Of 4 What Is The Probability That A Data Value Is Between 59 And 67 Round Your Answer To class=

Sagot :

858654189idn

Answer:

66.8% or 0.66772

Step-by-step explanation:

0.66772

Given that :

Mean (m) = 62

Standard deviation (s) = 4

probability that a data value is between 57 and 65

P(57 < x < 65)

Using the relation :

(x - m) / s

P(x < 57) :

(57 - 62) / 4 = - 1.25

P(Z < - 1.25) = 0.10565 ( Z probability calculator)

P(x < 65) :

(65 - 62) / 4 = 0.75

P(Z < 0.75) = 0.77337 (Z probability calculator)

P(Z < 0.75) - P(Z < - 1.25)

0.77337 - 0.10565 = 0.66772

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