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) For a direct-mapped cache design with a 32-bit address, the following bits of the address are used to access the cache. Tag Index Offset 31-10 9-5 4-0 a. What is the cache block size (in words)

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Baraqidn

Considering the description above, the cache block size (in words) is 2 words.

What is Cache block size?

Cache block size is generally known as pieces of memory that can be 4, 8, 16, or 32 KiBs in size.

The storage array's controller arranges cache block sizes.

Cache block size in this case

In this case, we have the index as 5 bits(9-5+1), and therefore the cache has 2^5 = 32 entries.

Block size = 2^5= 32bytes

Therefore, since one word is usually 16 bit, this is a 2 words.

32 bytes / 16bits = 2 words.

Hence, in this case, it is concluded that the correct answer is 2 words.

Learn more about Bytes and Bits here: https://brainly.com/question/24727087

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