Answered

IDNLearn.com offers a reliable platform for finding accurate and timely answers. Ask anything and receive comprehensive, well-informed responses from our dedicated team of experts.

System of Equations 7x+8y = 23 and 8x-4y = 0

Sagot :

Answer:

x = 1

y = 2

Step-by-step explanation:

Solve by substitution

1) Solve for x in 7x + 8y = 23

x = 28 - 8y/7

2) Substitute x = 23-8y/7 into 8x - 4y = 0

8(23-8y)/7 - 4y = 0

3) Solve for y in 8(23-8y)/7 - 4y = 0

y = 2

4) Substitute y = 2 into x = 23-8y/7

x = 1

5) Therefore,

x = 1

y = 2

Loneguyidn

[tex]7x+8y -23=0 ~~~\\\\8x-4y+0 =0\\\\\text{Using cross multiplication method,}\\\\\\\dfrac{x}{8(0)- (-23)(-4)} = \dfrac{y}{8(-23) -7(0)} = \dfrac 1{7(-4) - (8)(8)}}\\\\\\\implies \dfrac x{0-92} = \dfrac y{-184-0} =\dfrac 1{-28 -64}\\\\\\\implies -\dfrac x{92} = -\dfrac{y}{184} = - \dfrac 1{92}\\\\\\\implies \dfrac{x}{92} = \dfrac y{184} = \dfrac 1{92}\\\\\text{Hence,}\\\\x= \dfrac{92}{92} = 1\\\\y= \dfrac{184}{92} = 2[/tex]

Thank you for using this platform to share and learn. Keep asking and answering. We appreciate every contribution you make. Thank you for choosing IDNLearn.com. We’re dedicated to providing clear answers, so visit us again for more solutions.