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Sagot :
The distance traveled by the box over the first 4 s is 16 m.
To solve the problem above, First, we apply newton's Fundamental equation of force.
Newton's fundamental equation of force:
F = ma...................... Equation 1
Where
- F = Force
- m = mass of the box
- a = acceleration
make "a " the subject of the equation
a = F/m...................... Equation 2
From the question,
Given:
- F = 10 N
- m = 5 kg
Substitute these values into equation 2
a = 10/5
a = 2 m/s²
Finally, we use the equation of motion to calculate the distance it will travel over the given period of time.
Equation of motion
s = ut+at²/2........................... Equation 3
Where:
- s = total distance traveled
- t = time
- u = initial velocity
Given:
- t = 4 s
- u = 0 m/s (at rest)
- a = 2 m/s²
Substitute these values into equation 3
- s = 0(4)+(2×4²)/2
- s = 0+32/2
- s = 16 m
Hence, the distance traveled by the box over the first 4 s is 16 m
Learn more about Newton's fundamental equation here: https://brainly.com/question/13370981
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