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Consider the most common ions formed by fluorine (F–), sodium (Na+), magnesium (Mg2+), and aluminum (Al3+), respectively. How many electrons does each of these ions have?

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The ions F⁻, Na⁺, Mg²⁺, and Al³⁺ have 10 electrons, as Ne, the closest noble gas.

To determine the number of electrons of an ion, we need to consider:

  • The atomic number (Z): It establishes the number of protons and electrons in the neutral species.
  • The charge: It indicates the number of electrons gained (negative charge) or lost (positive charge).

  • Fluorine (F⁻)

F has 9 electrons (Z = 9) and it gains 1 electron to form F⁻. The total number of electrons is 9 + 1 = 10.

  • Sodium (Na⁺)

Na has 11 electrons (Z = 11) and it loses 1 electron to form Na⁺. The total number of electrons is 11 - 1 = 10.

  • Magnesium (Mg²⁺)

Mg has 12 electrons (Z = 12) and it loses 2 electrons to form Mg²⁺. The total number of electrons is 12 - 2 = 10.

  • Aluminum (Al³⁺)

Al has 13 electrons (Z = 13) and it loses 3 electrons to form Al³⁺. The total number of electrons is 13 - 3 = 10.

The ions F⁻, Na⁺, Mg²⁺, and Al³⁺ have 10 electrons, as Ne, the closest noble gas.

Learn more about ions here: https://brainly.com/question/3110170

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