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Sagot :
The plane descends, on average, 42.22 feet per second.
Given that an airplane flying at 15, 000 ft descends to land at an airport, and during the airplane's final approach it descends from 15,000 ft to 7, 400 ft in 3 min, to determine the average descent per second, the following calculation must be performed:
- (15,000 - 7,400) / (3 x 60) = X
- 7600/180 = X
- 42.22 = X
Therefore, the plane descends, on average, 42.22 feet per second.
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