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PLS ANSWER FAST The sum of twice a number and 7 times another number is 49. The first number decreased by 3 times the second number is 5. Enter the larger of the two numbers.

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Answer:  3 and 14

Step-by-step explanation:

Let the two numbers be X and Y.

"The sum of twice a number and 7 times another number is 49:"

2X + 7Y = 49

"The first number decreased by 3 times the second number is 5:"

X - 3*Y = 5

Rewrite the second equation so that either the X or Y is isolated.  I'll choose X:

X = 5+3Y

Now use this definition of X in the first equation:

2X + 7Y = 49

2(5+3Y) +7Y = 49

10 + 6Y + 7Y = 49

13Y = 39

Y = 3

Use Y = 3 to solve for X:

X - 3*Y = 5

X - 3*3 = 5

X = 5 + 9

X = 14

The values are X = 14 and Y = 3.

Check to see if these work:

2X + 7Y = 49

Does 2(14) + 7(3) = 49  ??

28 + 21 = 49  ?   YES

X - 3*Y = 5

Does 14 - 3*(3) = 5  ???

          14 - 9 = 5      YES

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