IDNLearn.com is the perfect place to get detailed and accurate answers to your questions. Our experts provide timely, comprehensive responses to ensure you have the information you need.
(a) The plane’s altitude when it released the cargo is 1,960 m.
(b) The speed of the plane when it dropped the cargo is 240 m/s.
The given parameters:
The plane’s altitude when it released the cargo is calculated as follows;
[tex]h = v_0_y t + \frac{1}{2} gt^2\\\\h = 0(20) \ + \ \frac{1}{2} (9.8)(20)^2\\\\h = 1,960 \ m[/tex]
The constant horizontal speed of plane when it dropped the cargo is calculated as follows;
[tex]v_x =\frac{X}{t} \\\\v_x = \frac{4800}{20} \\\\v_x =240 \ m/s[/tex]
Learn more about horizontal speed here:https://brainly.com/question/11381799