Answered

Find answers to your most challenging questions with the help of IDNLearn.com's experts. Explore thousands of verified answers from experts and find the solutions you need, no matter the topic.

A 10. kilogram wood box is at rest on a wood floor.  When a horizontal force is applied on the box toward the right, the box begins to gain speed at a constant, steady rate.  After a period of 5.0 seconds, the box has attained a velocity of 20. m/s.  What is the magnitude of the applied force?

Sagot :

Onyebuchinnajiidn

The magnitude of the applied force on the wood box is 40 N.

The given parameters;

  • mass of the wood box, m = 10 kg
  • initial velocity, u = 0
  • time of motion, t = 5 s
  • final velocity, v = 20 m/s

The acceleration of the wood box is calculated as follows;

[tex]a = \frac{v-u}{t} \\\\a = \frac{20 - 0}{5} \\\\a = 4 \ m/s^2[/tex]

The magnitude of the applied force on the wood box is calculated as follows;

[tex]F = ma\\\\F = 10 \times 4\\\\F = 40 \ N[/tex]

Learn more here about applied force here:https://brainly.com/question/2733221

We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Discover insightful answers at IDNLearn.com. We appreciate your visit and look forward to assisting you again.