Answered

Expand your horizons with the diverse and informative answers found on IDNLearn.com. Get the information you need from our community of experts who provide accurate and comprehensive answers to all your questions.

An arrow is shot at a target 20 m away. The arrow is shot with a horizontal velocity of 80 m/s.

How long is the arrow in the air for?____s

How far does the arrow drop as it approaches the target?____m

Sagot :

Onyebuchinnajiidn

(1) The time of motion of the arrow is 0.25 s.

(2) The vertical height dropped by the arrow as it approaches the target is 0.31 m.

The given parameters:

  • Horizontal distance of the arrow, X = 20 m
  • Horizontal speed of the arrow, v = 80 m/s

The time of motion of the arrow is calculated as follows;

[tex]t = \frac{X}{v} \\\\t = \frac{20 }{80} \\\\t = 0.25 \ s[/tex]

The vertical height dropped by the arrow as it approaches the target is calculated as follows;

[tex]h = v_0_y t + \frac{1}{2} gt^2\\\\h = 0 \ + \ \frac{1}{2} \times 9.8 \times 0.25^2\\\\h =0.31 \ m[/tex]

Learn more about time of motion of projectile here:  https://brainly.com/question/1912408

Thank you for joining our conversation. Don't hesitate to return anytime to find answers to your questions. Let's continue sharing knowledge and experiences! IDNLearn.com has the solutions you’re looking for. Thanks for visiting, and see you next time for more reliable information.