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The sum of twice a number and 7 times another number is 49. The first number decreased by 3 times the second number is 5. Enter the larger of the two numbers.

Sagot :

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Answer:

The larger of the two numbers is the first number which is 14

Step-by-step explanation:

2x+7y=49

x-3y = 5

2x-6y=10

13y=39

y=3

x-9=5

x=14, y=3

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