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A ball with a mass of 65 g flies with a velocity of 25 m/s. It is hit with a bat, whereby it gets a velocity of 35 m/s in the opposite direction. What is the average force that the bat acts on the ball with if the ball touches the bat for 4.0 ms?

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Onyebuchinnajiidn

The average force the bat exerts on the ball when it touches it for the given period of time is 975 N.

The given parameters:

  • mass of the ball, m₁ = 65 g
  • initial velocity of the ball, v₁ = 25 m/s
  • final velocity of the ball, v₂ = 35 m/s opposite direction
  • time of action, t = 4 ms

The average force the bat exerts on the ball when it touches it for the given period of time is calculated by applying Newton's second law as follows;

[tex]F = ma\\\\F = \frac{M(v_2 - v_1)}{t} \\\\F = \frac{0.065(35 - (-25))}{4 \times 10^{-3}} \\\\F = \frac{0.065(35 + 25)}{4 \times 10^{-3}} \\\\F = 975 \ N[/tex]

Thus, the average force the bat exerts on the ball when it touches it for the given period of time is 975 N.

Learn more about Newton's second law here: https://brainly.com/question/19887955

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