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The diagram below shows a 5.0-kilogram mass sliding 9.0 meters down an incline from a height of
2.0 meters in 3.0 seconds. The object gains 90. joules of kinetic energy while sliding.
How much work is done against friction as the mass slides the 9.0 meters?

Sagot :

Onyebuchinnajiidn

The work done against friction as the mass slides is 8 J.

The given parameters:

  • sliding mass, m = 5.0 kg
  • distance traveled by the mass, s = 9.0 m
  • height of incline, h = 2.0 m
  • time of motion, t = 3.0 s
  • kinetic energy of the object, K.E = 90 J

The work done against friction as the mass slides can be determined by applying work-energy theorem.

[tex]\Delta E= W\\\\P.E - K.E = W[/tex]

the change in mechanical energy of the sliding mass, is equal to energy lost to friction.

[tex]W = P.E - K.E\\\\W = mgh - K.E\\\\W = (5 \times 9.8 \times 2) - 90\\\\W = 98 - 90\\\\W = 8 \ J[/tex]

Thus, the work done against friction as the mass slides is 8 J.

Learn more about work-energy theorem here:https://brainly.com/question/10063455

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