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A new computer chip contains 4.71×1022 Si atoms. Determine the mass (in grams) of the silicon present in the computer chip.

Round to the tenths place.

Sagot :

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The mass (in grams) of the silicon present in the computer chip is 2.19 g

From Avogadro's hypothesis,

6.02×10²³ atoms = 1 mole of Si

But

1 mole of Si = 28 g

Thus, we can say that:

6.02×10²³ atoms = 28 g of Si

  • With the above information, we can obtain the mass of silicon, Si present in the computer chip. This can be obtained:

6.02×10²³ atoms = 28 g of Si

Therefore,

4.71×10²² atoms = (4.71×10²² × 28) / 6.02×10²³ g of Si

4.71×10²² atoms = 2.19 g of Si

Thus, the mass of silicon, Si present in the computer chip is 2.19 g

Learn more on Avogadro's number: https://brainly.com/question/25811549

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