Missvu15idn
Answered

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If cot of theta is the square root of 3, calculate (sin of theta)(cot of theta) - cos^2 of theta (in exact numbers)

Sagot :

GMillaridn

Answer:

\frac{\sqrt{3} }{2}  - .75

Step-by-step explanation:

cot Θ = Sqrt (3)

SinΘ = 1/2                         CscΘ = 2

CosΘ = Sqrt3 /  2              SecΘ = 2Sqrt3 / 3

TanΘ = Sqrt3 / 3               CotΘ = Sqrt (3)

Cotangent is Adjacent over Opposite

Adjacent = Sqrt 3

Opposite = 1

That means the Hyp = 2 (Pythag Theorem)

Sin Θ * Cot Θ - CosΘ ² =

1/2 * Sqrt 3 - .75 = (Sqrt3 / 2) - .75

Sqrt3 / 2 - .75 is as far as I can get.

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