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Sagot :

Answer:

Step-by-step explanation:

logx[tex]y^{2}[/tex] <=> logx + 2logy = a (1)

log[tex]x^{3}[/tex]y=b <=> 3logx + 6logy =b (2)

(1),(2)=> logx= [tex]\frac{-3a+2b}{3}[/tex]

            logy= 3a-b

=> log[tex]\frac{y}{x}[/tex]=logy-logx=3a-b -( [tex]\frac{-3a+2b}{3}[/tex]) = [tex]\frac{12a-5b}3}[/tex]

   log[tex]\sqrt{xy}[/tex] = [tex]\frac{1}{2}[/tex](logx+logy)=........ OK

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