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[tex]\huge \sf༆ \: question \: ༄[/tex]


Need Help with this question ~

A man of mass 50 kg is pulling on a plank of mass 100kg kept on a smooth floor as shown with force of 100 N. If both man and plank move together find the force of friction acting on the man.


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Texhuge Sf Question TexNeed Help With This Question A Man Of Mass 50 Kg Is Pulling On A Plank Of Mass 100kg Kept On A Smooth Floor As Shown With Force Of 100 N class=

Sagot :

Answer:

The man is standing on the plank then he is pulling the rope towards himself. He pushes forward with the legs so that pushes the plank "rope backwards

So that friction f acts in forward direction the plank.

The tension T in the rope is 100 N

[tex](A)  \frac{100}{3}  N  \: towards \: left[/tex]

the fiction force f newtons.

[tex]Man's \:  F _{net} ⇒T−F=ma[/tex]

[tex]F _{net}  (man)⇒T−F=50a[/tex]

[tex]Plank  Fnet ⇒T+f=ma[/tex]

[tex]F _{net}  ( plank)⇒T+f=lov \: a[/tex]

[tex]As T=100 N[/tex]

[tex]a = \frac{4}{3} {m/s}^{2} [/tex]

[tex]f = \frac{100}{3} \: newton[/tex]

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RainbowPassion120idn

Answer:

  • The mass of man=[tex]50kg[/tex]
  • The mass of plank=[tex]100kg[/tex]

Man applies a force of 100 N,therefore,F=100N.

[tex]m=m_o+m_p[/tex]

  • Substituting the values, we get.

[tex]m = 50 + 100[/tex]

[tex] \implies{m = 150 kg}[/tex]

Now,

We know that F=[tex]100 N[/tex]

  • The formula of the acceleration of system:

[tex] \implies{ \displaystyle{ a = \frac{F}{m} }}[/tex]

[tex] \implies{ \displaystyle{a = \frac{100}{150} }}[/tex]

[tex]\therefore{ \displaystyle{a = \frac{2}{3}m/ {s}^{2} }}[/tex]

Now,let's find the fiction force acting on the man.

[tex]F=m_oa[/tex]

[tex]F=50×\frac{2}{3}[/tex]

[tex]\therefore F=\frac{100}{3} N[/tex]

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