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Sagot :

Hnori22003idn

S (ABCD) = S (ABC) + S (ADC)

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Reminder :

Area of the triangle = ½ × base × height

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Thus :

[tex]S (ABCD) = ( \frac{1}{2} \times 10 \times 3) + ( \frac{1}{2} \times 10 \times 5) \\ [/tex]

[tex]S (ABCD) = 15 + 25[/tex]

[tex]S (ABCD) = 40 \: \: {cm}^{2} [/tex]

There you go...

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