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Sagot :
The fifth term of the geometric progression is 6.75
Given the geometric progression 4/3, 18/9, 1, 16/27...
The nth term of a geometric progression is expressed according to the equation [tex]a_n=ar^{n-1}[/tex]
- a is the first term of the sequence
- n is the number of terms
- r is the common ratio
Given the following parameters;
a = 4/3
r = 18/9 * 3/4 = 3/2
n = 5
Substitute the given values into the formula
[tex]a_5=\frac{4}{3}(\frac{3}{2} )^{5-1}\\a_5 =\frac{4}{3}(\frac{3}{2} )^{4}\\a_5=\frac{4}{3}(5.0625)\\a_5=6.75[/tex]
Hence the fifth term of the geometric progression is 6.75
Learn more on GP here: https://brainly.com/question/25274096
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