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An airplane starts from rest on a runway, there is no wind on this day.the plane accelerates uniformly for 38 seconds until it reaches an air speed 150 mph and lifts off the run way.


a. calculate the acceleration of the plane


b. calculate the minimum length of the runway required for this takeoff


c. would the plane be able to take off if the runway is 980 m, Justify your answer


use SI units

please help. if i dont get this right ill fail physics

Sagot :

Boffeemadrididn

The acceleration, take off length and possibility of the airplane flying is required.

Acceleration of the plane is [tex]1.76\ \text{m/s}^2[/tex]

Minimum distance required to takeoff is 1277.57 m

It would not be able to fly if the runway was 980 m.

v = Final velocity = [tex]150\times \dfrac{1609.34}{3600}=67.06\ \text{m/s}[/tex]

u = Initial velocity = 0

s = Displacement

t = Time = 38 s

a = Acceleration

From the kinematic equations we get

[tex]v=u+at\\\Rightarrow a=\dfrac{v-u}{t}\\\Rightarrow a=\dfrac{67.06-0}{38}\\\Rightarrow a=1.76\ \text{m/s}^2[/tex]

[tex]v^2-u^2=2as\\\Rightarrow s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{67.06^2-0}{2\times 1.76}\\\Rightarrow s=1277.57\ \text{m}[/tex]

The minimum distance required to takeoff is 1277.57 m.

So, if the runway was 980 m it would not be able to fly.

Learn more:

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