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The length of one of the parallel sides of a trapezium is 5 more than the other parallel side. The perpendicular height is 7 cm. Write an expression for the area

Sagot :

CrazyMoosenidn

Answer:

7x+35/2

Step-by-step explanation:

The area of a trapezoid is [tex]\frac{(b_1+b_2)}{2}\cdot h[/tex], where b1 and b2 are the two bases and h is the height. Because b2 is 5 more than b1, which we will represent as x, we have the two bases as x and x + 5 respectively. Plugging into the equation, we have [tex]\frac{2x+5}{2}\cdot 7[/tex] .We have this as (x+5/2)(7), which is 7x+35/2

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